Thread: Trigonometry
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Old 09-08-2008, 07:27 PM   #4
GTX2GvO
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Join Date: Feb 2007
Location: Schijndel, Netherlands
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Quote:
Originally Posted by Mighty Midget View Post
The "IRL" problem was: At time t = 0 I had a ship at bearing x. 3 minutes later the bearing had changed to y, and 3 minutes later the bearing was z. From these data I wondered if I could calculate the ship's course.
We GOT E!!!!

How?? Well Easy.. the full length of e is 6 minutes CONSTANT SPEED
Half an e is 3 minutes CONSTANT SPEED..

So when stated that line c (AC) should also be a known, I can say:
Line c (AC) is 5 minutes Long...

Knowing all angles @ A also you can EASILY calculate ALL remaining angles and Distances in degrees and Minutes of CONSTANT SPEED..

So let's say.. Angle Alfa (BAC) is 18* and Angle Beta (CAD) is 24*.

Now I COULD calculate the rest of it all.....

But not @ this hour... (and not without the proper tools (paper calculator))

So I'll get back on this some other time...
(If it's still an issue that needs to be solved)
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