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Old 15-01-2005, 03:59 AM   #1
Kon-Tiki
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Hehehe, alright k: Most people just give up as soon as something looks like it's over their heads, so I assumed that.

Stuck at something else again. How can I calculate the limit for 2 in
x?-x-2
--------
x?-3x+2

I know I have to work that lower part away by simplifying both upper and lower part, but I can't figure out how exactly.
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Old 15-01-2005, 10:41 AM   #2
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I haven't done this for a couple weeks. Been on holidays, and my brain has gone numb from it. But I think you divide through by the x?, then solve. But of course I have gotten really lazy in maths lately due to the amount of work that is required so I don't know much.
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Old 15-01-2005, 10:48 AM   #3
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about number five: if 0/0 apears in a limit then you take the derivative of both parts:

so
9-x => -1

x^1/2 -3 => 1/2* x^-1/2 (fill x=9 :1/6 )

result is -1 / (1/6) = -6
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Old 15-01-2005, 10:51 AM   #4
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Quote:
Originally posted by Kon-Tiki@Posted on Jan 15 2005, 12:00 AM
How do they get -6 then instead of 0? Or in this case, very close to -6 instead of very close to 0?
But before when they got -6 for the answer. When x approaches 9 the easiest number to use that is close to 9 is 10, you may use 8. So replace all x's with 8 or 10.

Square root of 10 it between 3 and 4 but closer to 3. So you will have (-1)(6)/1.

Square root of 8 is between 2 and 3 but closer to 3. So you will have (1)(6)/-1.

Both equal -6.
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Old 15-01-2005, 12:16 PM   #5
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This is a simple math issue for limits. I'll say it in dutch.

Als het originele antwoord 0/0 is dan moet je de teller en de noemer ontbinden in factoren.
Dan moet je de storende factor wegdelen en dan de x vervangen door het oorsprongkelijk in te vullen getal.

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Old 15-01-2005, 12:31 PM   #6
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Quote:
Originally posted by Kon-Tiki@Jan 15 2005, 04:59 AM
Hehehe, alright k: Most people just give up as soon as something looks like it's over their heads, so I assumed that.

Stuck at something else again. How can I calculate the limit for 2 in
x?-x-2
--------
x?-3x+2

I know I have to work that lower part away by simplifying both upper and lower part, but I can't figure out how exactly.
i hired a private tutor once, and for 30 minutes i understood perfectly vectors and matrices that id never been able to grasp.

my brain rejected this revelation after a day, and it was like chinese to me again.

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Old 15-01-2005, 12:58 PM   #7
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Quote:
Originally posted by Kon-Tiki@Jan 15 2005, 06:59 AM
Stuck at something else again. How can I calculate the limit for 2 in
x?-x-2
--------
x?-3x+2

I know I have to work that lower part away by simplifying both upper and lower part, but I can't figure out how exactly.
Simplify and you get:

(x - 2) (x + 1) (x+1)
-------------- = ---------
(x - 2) (x - 1) (x-1)

Now just go on from there!
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Old 15-01-2005, 02:03 PM   #8
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Thanks all k: Now on to the next parts. Still so much to study, far from enough time :not_ok:
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Old 15-01-2005, 03:19 PM   #9
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OMG these are the exercises i do at school
I hate limits!(that's how my lesson is called) :ranting:

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